5((t^2)-3t+2)=t(5t-2)

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Solution for 5((t^2)-3t+2)=t(5t-2) equation:



5((t^2)-3t+2)=t(5t-2)
We move all terms to the left:
5((t^2)-3t+2)-(t(5t-2))=0
We multiply parentheses
5t^2-15t-(t(5t-2))+10=0
We calculate terms in parentheses: -(t(5t-2)), so:
t(5t-2)
We multiply parentheses
5t^2-2t
Back to the equation:
-(5t^2-2t)
We get rid of parentheses
5t^2-5t^2-15t+2t+10=0
We add all the numbers together, and all the variables
-13t+10=0
We move all terms containing t to the left, all other terms to the right
-13t=-10
t=-10/-13
t=10/13

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